9[z-(8z+16)+2]=3(z+2)

Solution for 9[z-(8z+16)+2]=3(z+2) equation:

Simplifying
9[z + -1(8z + 16) + 2] = 3(z + 2)

Reorder the terms:
9[z + -1(16 + 8z) + 2] = 3(z + 2)
9[z + (16 * -1 + 8z * -1) + 2] = 3(z + 2)
9[z + (-16 + -8z) + 2] = 3(z + 2)

Reorder the terms:
9[-16 + 2 + z + -8z] = 3(z + 2)

Combine like terms: -16 + 2 = -14
9[-14 + z + -8z] = 3(z + 2)

Combine like terms: z + -8z = -7z
9[-14 + -7z] = 3(z + 2)
[-14 * 9 + -7z * 9] = 3(z + 2)
[-126 + -63z] = 3(z + 2)

Reorder the terms:
-126 + -63z = 3(2 + z)
-126 + -63z = (2 * 3 + z * 3)
-126 + -63z = (6 + 3z)

Solving
-126 + -63z = 6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-126 + -63z + -3z = 6 + 3z + -3z

Combine like terms: -63z + -3z = -66z
-126 + -66z = 6 + 3z + -3z

Combine like terms: 3z + -3z = 0
-126 + -66z = 6 + 0
-126 + -66z = 6

Add '126' to each side of the equation.
-126 + 126 + -66z = 6 + 126

Combine like terms: -126 + 126 = 0
0 + -66z = 6 + 126
-66z = 6 + 126

Combine like terms: 6 + 126 = 132
-66z = 132

Divide each side by '-66'.
z = -2

Simplifying
z = -2